From c3bff3fb32dbf457ee5e9817153811d3f63b8fbe Mon Sep 17 00:00:00 2001
From: Mike Buland <eichlan@xagasoft.com>
Date: Fri, 4 Sep 2009 16:15:38 +0000
Subject: Wow, I should check this in the other containers.  I should have
 known better, but I made the Formatter << operator for Lists use the List
 with the value as the template parameter, and no others, so if you actually
 tune the list, you can't format it anymore.  This has been fixed.

---
 src/list.h | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)

diff --git a/src/list.h b/src/list.h
index 785a95c..12b50e5 100644
--- a/src/list.h
+++ b/src/list.h
@@ -766,11 +766,11 @@ namespace Bu
 	class Formatter;
 	Formatter &operator<<( Formatter &rOut, char *sStr );
 	Formatter &operator<<( Formatter &rOut, signed char c );
-	template<typename value>
-	Formatter &operator<<( Formatter &f, const Bu::List<value> &l )
+	template<typename a, typename b, typename c, typename d>
+	Formatter &operator<<( Formatter &f, const Bu::List<a,b,c,d> &l )
 	{
 		f << '[';
-		for( typename Bu::List<value>::const_iterator i = l.begin(); i; i++ )
+		for( typename Bu::List<a,b,c,d>::const_iterator i = l.begin(); i; i++ )
 		{
 			if( i != l.begin() )
 				f << ", ";
-- 
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